The possible outcomes are — 1, 2, 3, 4, 5, and 6. The probability of getting any of the outcomes is 1/6. As the possibility of happening of an event is an equally probably event there is like casual of getting any number, in this case, it is either 1/6 or 50/3 %. **Formula of Probability**

probability of an event = { Number of ways it can occur } ⁄ { total number of outcomes } P ( A ) = { Number of ways A occur } ⁄ { total count of outcomes }

### Types of Events

**Equally Likely Events:**After rolling dice, the probability of getting any of the likely events is 1/6. As the event is an equally likely event there is same possibility of getting any number, in this case, it is either 1/6 in fair dice rolling.**Complementary Events:**There is a possibility of only two outcomes which is an event will occur or not. Like a person will play or not play, buying a laptop or not buying a laptop, etc. are examples of complementary events.

### What is the probability of getting 10 heads in 20 flips?

**Solution:**

Each coin can either land on heads or on tails, 2 choices. ( According to binomial concept ) This gives us a total of 220 possibilities for flipping 20 coins. now how many ways can we get 10 heads ? This is 20 choose 10, or ( 20C10 ) This means our probability is ( 20C10 ) /220= 184756⁄1048576 ≈ .1762

**Similar Questions**

**Question1: What is the probability of 10 heads in 10 coins tossed together.?** **Solution:**

If the mint is bonny, then the probability of getting either a head or a fag end is 0.5.

According to binomial concept

So the probability of getting 10 heads in a quarrel is 0.510≈0.00098 which is 1 in 1024 .

**Question 2: What is the probability of 5 in 5 coins tossed together.?** **Solution:**

5 coin tosses. This means, total observations = 25 ( According to binomial concept ) Required consequence → 5 Heads { H, H, H, H, H } This can occur only once ! therefore, required result =1 Probability ( 5 Heads ) = ( 1⁄2 ) 5 = 1/32

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